x-(3-x)^(1/2)=-3

Solution for x-(3-x)^(1/2)=-3 equation:

x-(3-x)^(1/2)=-3

We move all terms to the left:

x-(3-x)^(1/2)-(-3)=0

We add all the numbers together, and all the variables

x-(-1x+3)^(+1/2)-(-3)=0

We add all the numbers together, and all the variables

x-(-1x+3)^(+1/2)+3=0

We multiply all the terms by the denominator


x*2)-(-1x+1+3)^(+3*2)=0

We add all the numbers together, and all the variables

x*2)-(-1x+4)^6=0

We add all the numbers together, and all the variables

-1x+x*2)-(=0

Wy multiply elements

2x^2-1x=0

a = 2; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·2·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*2}=\frac{0}{4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*2}=\frac{2}{4}
=1/2
$